(p2+q2)(x-1)=pq(2x-y). 4x=y+2

Dear Student, (p^{2} + q^{2}) (x - 1) = pq (2 x - y) 4 x = y + 2 (p^{2} + q^{2}) (\frac{y + 2}{4} - 1) = pq (\frac{y + 2}{2} - y) (p^{2} + q^{2}) (y - 2) = 2 pq (2 - y) p^{2} + q^{2} + 2 pq = 0 or y = 2 {(p + q)}^{2} = 0 or y = 2 p = - q or y = 2 So x = 1 Regards