One litre of mixture of CO and CO2 is passed through red hot charcoal in a tube The new - Chemistry - Redox Reactions

Question

One litre of mixture of CO and CO2 is passed through
red hot charcoal in a tube The new volume becomes 1 4litres Find
out percentage composition of the mixture b volume All measurements
are made at same P and T

Mann Verlekar · Answer

Equation of the reaction:
CO2 + C = 2CO
According to equation, when 1 litre of CO2 reacts with 1 mol of
coke, twolitres of CO are formed Our mixture of gases has volume 1
4 L Thus it is
composed from CO and non-reacted CO2
If x litres of CO2 are reacted, 2x liters of CO are formed Total
volume ofmixture is the sum of CO2 and CO volumes:
V(mixture) = V(new volume CO2) + V(CO) = 1 4 L
V(new volume CO2) = V(initial volume CO2) - V(reacted CO2) = (1 -
x) L
V(CO) = 2x
So, we have equation:
1 4 = 1 - x + 2x
The solution is x = 0 4 L
Thus, the mixture consist from 1-0 4=0 6 L of CO2 and 2*0 4=0 8 L
of CO (iii)
Answer: (iii)
The composition of product is 0 6 ltr of CO2 and 0 8 ltr of CO

One litre of mixture of CO and CO2 is passed through red hot charcoal in a tube. The new volume becomes 1.4litres. Find out percentage composition of the mixture b volume. All measurements are made at same P and T.

One litre of mixture of CO and CO₂is passed through red hot charcoal in a tube. The new volume becomes 1.4litres. Find out percentage composition of the mixture b volume. All measurements are made at same P and T.