One liquid has a specific gravity of 0.7 . and another liquid has a density of 0.4 g/cc  The  thermal capacity of 4 litre of the first is the same as that of 3.5 litres of the second . Compare their specific heats.

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We have

Q=CVMdtM=ρVNow specific gravity ofliq A= ρAρwater=ρA as water density is 1 g/ccNow MA=ρAVA  similarly, MB=ρBVBAs givenCVAρAVA =CVBρBVBor,  CVACVB=ρBVBρAVA 0.4×3.50.7×41.42.812


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