OF THE 3ANGLE OF A TRIANgle ONE IS TWICE THE SMALLEST ISTHRICE THE SMALLLEST ANGLE FIND ALL THE ANGLE?
Let angle A be x, angle be= y and abgle C =z.
According to quetion, x+y = 65.....(i)
. and y+z = 140......(ii)
From (i) we have, x+y = 65. so y= 65-x.......(A)
From (ii) we have, y+z = 140. If we put the value of y as we got in (A), we get, (65-x) +z =140, so z = 140 - (65-x) = 140 - 65 +x = 75 + x ......(B).
Now we know sum of all angles to triangle = 180.
So, x + y +z = 180.
If we exchange the value of "y" and "z", which we got in "A" and "B", we get :-
x + (65-x) + (75 +x)= 180.
x + 65 -x + 75 +x = 180
140+x=180.
So x= 40 degrees.
Now ,
y = 65 - 40 = 25 .
z = 140 - 25= 115.
Hope you got it :)