No links please Chapter name : Vector Q14. ABCD is a parallelogram ; p and Q are the mid-points of the sides A B and D C respectively. Show that DP and BQ trisect A C and are trisected by A C . Share with your friends Share 1 Lovina Kansal answered this Dear student Taking O as origin, let the position vector B and D be b→ and d→ respectively.Then position vector of C is b→+d→Since P and Q are the mid points of AB and CD respectively. So, position vectorsof P and Q are b→2 and b→2+d→ respectively.The position vector of a point dividing AC in the ratio 1:2 is1.b→+d→+2.0→1+2=b→+d→3Also, the position vector of the point dividing DP in the ratio 2:1 is2b→2+1.d→2+1=b→+d→3Thus, the point of trisection of AC coincides with the point of trisection of DP.Hence, DP cuts the diagonals AC in its point of trisection, which is also the point of trisection of DP.Similalrly, BQ cuts the diagonal AC in its point oftrisection, which is also the point of trisection of BQ. Regards 0 View Full Answer