No links please Chapter name: Vector 19 . T h e d i a g o n a l s o f t h e p a r a l l e log r a m A B C D i n t e r s e c t a t E . I f a → , b → , c → a n d d → b e t h e p o s i t i o n v e c t o r s o f i t s v e r t i c e s w i t h r e s p e c t t o a n a r b i t r a r y o r i g i n O , t h e n s h o w a → + b → + c → + d → = 4 O E → . Share with your friends Share 0 Neha Sethi answered this Dear student Solution: E is the mid point of AC.So, OE→=OA→+OC→22OE→=OA→+OC→ ...1Also, E is the mid point of BDOE→=OB→+OD→22OE→=OB→+OD→ ...2On adding 1 and 2, we get2OE→+2OE→=OA→+OC→+OB→+OD→4OE→=OA→+OC→+OB→+OD→4OE→=a→+b→+c→+d→ Regards 0 View Full Answer