n(A-B)=30, n (B-A)=18 and n(AuB)=50 find n(AnB) - Maths - Sets

Question

n(A-B)=30, n (B-A)=18 and n(AuB)=50
find n(AnB)

Santosh Kumar · Accepted Answer

$n (A - B) = 30, n (B - A) = 18 n (A \cup B) = 50$ Unshaded part is (Aâˆ©B) $∴ n (A \cap B) = n (A \cup B) - [n (A - B) + n (B - A)] = 50 - (30 + 18) = 50 - 48 = 2$