(n+2)! . (2n+1)! = 72 (2n-1)! (n+3)! 7 Share with your friends Share 2 Ishwarmani answered this Dear Student, Please find below the solution to the asked query: We have,n+2!2n-1!×2n+1!n+3!=727⇒n+2!2n-1!×2n+1×2n×2n-1!n+3×n+2!=727⇒2n2n+1n+3=727⇒74n2+2n=72n+3⇒28n2+14n=72n+216⇒28n2-58n-216=0⇒14n2-29n-108=0⇒n=--29±-292-4×14-1082×14⇒n=29±841+604828⇒n=29±688928⇒n=29±8328⇒n=29+8328 As, n cannot be negative⇒n=11228∴ n=4 Regards 0 View Full Answer