(n+2)! . (2n+1)! = 72
(2n-1)!   (n+3)!      7

Dear Student,
Please find below the solution to the asked query:

We have,n+2!2n-1!×2n+1!n+3!=727n+2!2n-1!×2n+1×2n×2n-1!n+3×n+2!=7272n2n+1n+3=72774n2+2n=72n+328n2+14n=72n+21628n2-58n-216=014n2-29n-108=0n=--29±-292-4×14-1082×14n=29±841+604828n=29±688928n=29±8328n=29+8328     As, n cannot be negativen=11228 n=4

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