Methane is heated strongly in air to undergo complete combustion. calculate the no. of moles and amount of carbon dioxide formed when 6x102 molecules of methane burn
Reaction Involved-
CH4 + 2O2 → CO2 + 2H2O
1 mol of CH4 reacts with 2 mol of O2 to produce 1 mol of CO2
Thus,6.022 x 1023 molecules of CH4 = 6.022 x 1023 molecules of CO2
Thus,
6 x102 molecules of CH4 = 6x102 molecules of CO2
6x102 molecules of CO2 = 6 x 102 / 6.022 x 10 23 mol = 9.9 x 10-24 mol
Amount of CO2 produced
= (Moles) x (Molar mass)
= 9.9 x 10-24 mol x 44 g/mol
= 435.6 x 10-24 g
CH4 + 2O2 → CO2 + 2H2O
1 mol of CH4 reacts with 2 mol of O2 to produce 1 mol of CO2
Thus,6.022 x 1023 molecules of CH4 = 6.022 x 1023 molecules of CO2
Thus,
6 x102 molecules of CH4 = 6x102 molecules of CO2
6x102 molecules of CO2 = 6 x 102 / 6.022 x 10 23 mol = 9.9 x 10-24 mol
Amount of CO2 produced
= (Moles) x (Molar mass)
= 9.9 x 10-24 mol x 44 g/mol
= 435.6 x 10-24 g