merit nation expert.. i a now studying the study meterial and ncert question for math exam..we it be enough for me to score a good marks?

Share with your friends

Sudharsan Balajee answered this

Yes , Of Course

Study the study materaisl , Practise the NCERT textbook sums , Practisethe example sums in the NCERT textbook , Practise all the chapter tests and Model tests and finally Use the test generator and practise as much questions as you can.

If you recieved Correspondence test pack , then do all the sums in the book.

View Full Answer

Shreya Kundu answered this

i agree that meritnation study materials contain good quality questions but to be perfect in maths we should also referr to other books like RD OR RS and may some competitive exam books to practice similar type of questions and more high level question to get more confidence to solve any problem.

but for preliminary level first we should understand the concept and solve the questions from our ncert which is the must

HPE IT HELPS

Shreya Kundu answered this

but to get good marks in school study mat ,ncert and meritnaion tests which predics our level is more than enough

Subhan answered this

WE HAV TO DO ALL SUMS IN THE TEXTBOOK AND PRACTICE ATLEAST 5 QUESTION PAPERS

Shreya Kundu answered this

yes very important point that while solving cbsce sample papers do finish it within the time period and mark yurself out of 90 from this yu will come to know yur potential

Mohsin Musthafa answered this

show the diagram please

Posted by manassa akshaya(student) on 21/8/12

to prove - angle BOC = 90 ' - 1/2 angle A

proof. :- bo is bisector of angle CBE

then,

angle CBO= 1/2 CBE

= 1/2 (180 ' - angle ABC)

= 90 ' - 1/2 ABC............. eqn 1

similllarly. .

CO is bisector of angle BCD

angle BCO = 1/2 angle BCD

=1/2 (180 ' - angle ACB)

= 90 ' - 1/2 angle ACB......... eqn 2

.

in triangle BOC ,

angle BCO + angle BOC + angle CBO = 180 '

= 90 ' - 1/2 angle ABC + angle BOC + 90 ' - 1/2 ACB= 180 '

= 180 -1/2 ( angle ABC - angle ACB) + angle BOC = 180 '

= angle BOC = 1/2 ( angle ABC- angle ACB).........eqn 3

in traingle.. ABC ..,

angle ABC + angle ACB + angle BAC = 180 '

angle ABC + angle ACB = 180 ' - angle BAC.......eqn 4

substituting eqn 3 and 4 ,,

we get.. ,

angle BOC = 1/2 (180 ' - angle BAC)

= angle BOC = 90 ' - 1/2 angle A

proved. ...