limit x tends to zero sinx-2sin3x+sin5x / x^3 Share with your friends Share 5 Manbar Singh answered this limx→0sin x - 2 sin 3x + sin 5xx3=limx→0sin x + sin 5x - 2 sin 3xx3=limx→02 sin 3x. cos 2x-2 sin 3xx3=limx→02 sin 3xcos 2x - 1x3=-2limx→0sin 3x . 1-cos 2xx3=-2limx→0 sin 3x . 2 sin2xx3=-4limx→0sin 3xx . limx→0sin xx . limx→0sin xx=-12limx→0sin 3x3x . limx→0sin xx . limx→0sin xx=-12×1×1×1=-12 4 View Full Answer Cool@rohit - answered this use L'hospitals rule 3 time here..u will get the answer 1
