lim x tends to pi/2 cos 3x + 3cos x/ (pi/2 - x )^3 Share with your friends Share 0 Lalit Mehra answered this limx→π2cos3x+3cosxπ2-x3=limx→π24cos3x-3cosx+3cosxπ2-x3=limx→π24cos3xπ2-x3=4limx→π2sin3π2-xπ2-x3=4limx→π2sinπ2-xπ2-x3=4×13 limx→0sinxx=1=4 3 View Full Answer Rohit Goyal answered this Infinity 1