Let the angles A, B and C of ΔABC be in A.P and.

Find the measure of angle C.

  • A)

    30°

  • B)

    45°

  • C)

    60°

  • D)

    90°

Dear Student,
Please find below the solution to the asked query:

We have:A,B,Cin A.P.Let A,B,Cbe a-d,a,a+d respectively.Sum of all angles of triangle is 180°a-d+a+a+d=180°3a=180°a=60°B=60°a:b::1:3ab=13Using sine rule asinA=bsinB=csinC=k, we get:ksinAksinB=13sinAsin60°=13sinA32=132sinA=1sinA=12=sin30°A=30°A+B+C=180°30°+60°+C=180°C=90°...OptionD

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