Kindly solve sec 2 no 4
Dear student,
Van der wall's equation explains the behaviour of real gases with great accuracy and also the deviations of gas laws from ideal behaviour. Van der Waals introduced the necessary corrections as -
1. Volume correction: At higher pressure, the volume is much reduced and at this state the volume of gas molecules no longer remains negligible in comparison with the total volume V occupied by the gas. generally denoted by (b). And constant ‘b’ is the effective volume of the gas molecules hence it indicates that the gas molecules are incompressible.
2. Pressure correction: The pressure of a gas is due to the hits of the molecules on the walls of the containing vessel. generally denoted by (a). The value of ‘a’ is said to be a measure of the intermolecular forces of attraction.
Hence in above question both equation of state having only volume correction factor so that, the both gas molecules are incompressible.
correct option is (C) Neither gas(X) nor gas (Y) is Liquefiable.
WIth Regards!
Van der wall's equation explains the behaviour of real gases with great accuracy and also the deviations of gas laws from ideal behaviour. Van der Waals introduced the necessary corrections as -
1. Volume correction: At higher pressure, the volume is much reduced and at this state the volume of gas molecules no longer remains negligible in comparison with the total volume V occupied by the gas. generally denoted by (b). And constant ‘b’ is the effective volume of the gas molecules hence it indicates that the gas molecules are incompressible.
2. Pressure correction: The pressure of a gas is due to the hits of the molecules on the walls of the containing vessel. generally denoted by (a). The value of ‘a’ is said to be a measure of the intermolecular forces of attraction.
Hence in above question both equation of state having only volume correction factor so that, the both gas molecules are incompressible.
correct option is (C) Neither gas(X) nor gas (Y) is Liquefiable.
WIth Regards!