Kindly answer the question that follows below:

Solution:
If a constant voltage V is applied across the ends of the wire of resistance R, then heat generated
H=V2RtBut, R=ρLA=ρLπr2So, H=V2Rt         =πr2V2ρLt            Hr2L       So,H1H2=r1r22×L2L1   =r12r12×2L1L1   =14×2    =12H2=2×H1Hence, heat generated becomes double.  
 

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