Kindly ans the following

Solution :
Since it is given that Ramakrishnan cannot see beyond 1.4 m. So, any distance beyond it needs to be corrected to 1.4 m as focal length by lens.
Hence, power of corrective lens is given by,
P = 1/f
P = 1/1.4
P = 0.71 D
So, person should be wearing a diverging lens or Concave lens of power 0.71 D.
Hence, option A is the correct answer

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