In which compound both removal or addition of electron leads to decrease in bond order ?
1)O2   2)F2   3)N2   4)CO

The solution is as follows:


O2:σ1s2σ*1s2σ2s2σ*2s2σ2px2π2px2π2py2π*2px1π*2py1 Bond order = Nb-Na2=8-42=2O2+:σ1s2σ*1s2σ2s2σ*2s2σ2px2π2px2π2py2π*2px1π*2pyBond order = 8-32=2.5O2-:σ1s2σ*1s2σ2s2σ*2s2σ2px2π2px2π2py2π*2px2π*2py1Bond order = 8-52=1.5F2:σ1s2σ*1s2σ2s2σ*2s2σ2px2π2px2π2py2π*2px2π*2py2Bond order = 10-82=1F2+:σ1s2σ*1s2σ2s2σ*2s2σ2px2π2px2π2py2π*2px2π*2py1Bond order =10-72=1.5F2-:σ1s2σ*1s2σ2s2σ*2s2σ2px2π2px2π2py2π*2px2π*2py2σ*2px1Bond order = 10-92=0.5N2:σ1s2σ*1s2σ2s2σ*2s2π2px2π2py2σ2px2Bond order = 10-42=3N2+:σ1s2σ*1s2σ2s2σ*2s2π2px2π2py2σ2px1Bond order = 9-42=2.5N2-:σ1s2σ*1s2σ2s2σ*2s2π2px2π2py2σ2px2π2px1Bond order = 11-42=3.5CO:σ1s2σ*1s2σ2s2π2px2π2py2σ2px2σ*2s2Bond order =10-42=3CO+:σ1s2σ*1s2σ2s2π2px2π2py2σ2px2σ*2s1Bond order =10-32=3.5CO-:σ1s2σ*1s2σ2s2π2px2π2py2σ2px2σ*2s2π2px1Bond order =10-52=2.5
None of these molecules show decrease in bond order in both addition and removal of electrons.

  • -30
What are you looking for?