In triangle PQR point T is the mid point of median PS as shown in the given fig show that ar(triangle PQT)=1/4 ar(triangle PQR)
in the given figure ABC is a triangle with T the midpoint of median PS
To prove : ar (triangle PQT) = 1/4 ar(triangle PQR)
construction: join TR
ar(triangle PQS) = ar(triangle PSR)
therefore, half of Ar(triangle PQS) = half of Ar ( triangle PSR)
that is Ar(triangle PQT)=Ar(triangle PTR)...........(1)
and Ar(triangle QST) = Ar( triangle TSR)...........(2)
since, Ar (triangle PQR) =ar (triangles PQS + PSR )
but from (1) and (2)
ar (triangle PQR) = 2ar(trianlge PQS)
ar (triangle PQR) =2ar(2PQT)....from (1)
ar (triangle PQR) = 4 ar (triangle PQT )
therefore,ar(triangle PQT) = 1/4 ar (triangle PQR)
hope this helps if so, dont forget to make that thumbs up button go dark blue!!
To prove : ar (triangle PQT) = 1/4 ar(triangle PQR)
construction: join TR
ar(triangle PQS) = ar(triangle PSR)
therefore, half of Ar(triangle PQS) = half of Ar ( triangle PSR)
that is Ar(triangle PQT)=Ar(triangle PTR)...........(1)
and Ar(triangle QST) = Ar( triangle TSR)...........(2)
since, Ar (triangle PQR) =ar (triangles PQS + PSR )
but from (1) and (2)
ar (triangle PQR) = 2ar(trianlge PQS)
ar (triangle PQR) =2ar(2PQT)....from (1)
ar (triangle PQR) = 4 ar (triangle PQT )
therefore,ar(triangle PQT) = 1/4 ar (triangle PQR)
hope this helps if so, dont forget to make that thumbs up button go dark blue!!