In triangle ABC, D, E and F are respectively the mid-points of sides AB, BC, CA. show that triangle ABC is divided into four congruent triangles by joining D, E, and F.

Given that D, E and F are the mid points of sides AB, BC, CA respectively.

To show: ΔABC is divided into four congruent triangles

Proof: D is the mid point of AB

F is the mid point of AC.

∴DF||BC    (By mid point theorem)

⇒DF||BE    ......(1)

also E is the mid point of BC

and F is the mid point of AC.

∴EF||AB    (By mid point theorem)

⇒EF||DB    ......(2)

By (1) & (2)

BEFD is a parallelogram

⇒ΔBDEΔDEF   (Since diagonal of a parallelogram divides it into two congruent triangles)  ......(3)

Similarly

ΔDEFΔCEF    ......(4)

ΔDEFΔADF    ......(5)

By (3), (4) & (5)

We have,

Hence proved

  • 91
What are you looking for?