In triangle ABC, angle BAC is equal to 90 degree,seg AD is perpendicular to side BC and seg DE is - Maths - Pythagoras Theorem

Question

In triangle ABC, angle BAC is equal to 90 degree,seg AD is
perpendicular to side BC and seg DE is perpendicular to side AB,
then

Shashank Singh · Accepted Answer

In triangle ABC, angle BAC is equal to 90 degree,seg AD is perpendicular to side BC and seg DE is perpendicular to side AB, then