In triangle ABC, AB=3, BC=5 & Ac=7. If AD & CE are the angle bisectors meeting at P then find the ratio PD:AD.


Using angle bisector theorem, ABAC=BDDCBDDC=37BDDC+1=37+1CBDC=107......1and ACBC=AEBEAEBE=75...2AEBE+1=75+1ABBE=125Now in triangle CDA with same logic, CDAC=DPAD.....3But here something is missing so kindly recheck the question.

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