in the interval pi/2 x pi, find the value of x for the matrix [2sinx 3 - Maths - Determinants

Question

in the interval pi/2 < x < pi, find the value of x for the
matrix [2sinx 3 1 2sinx] is a 2x2 matrix, if it is singular

Lovina Kansal · Accepted Answer

Dear student
Since 2×2 matrix is singular
So, its determinant will be zero i
e 2sinx312sinx=0⇒4sin2x-3=0⇒sin2x=34⇒sinx=±32⇒sinx=sin2π3  as x∈π2,π⇒x=2π3
Regards

in the interval pi/2 < x < pi, find the value of x for the matrix [2sinx 3 1 2sinx] is a 2x2 matrix, if it is singular