IN the given figure LM PARALLEL TO NQ. FIND the value of X. Share with your friends Share 6 Devesh Kumar answered this Extend RQ such that it meets LM at P In triangle PMR∠PMR+∠MRQ+∠RPM=180° Angle sum propertyx+30+∠RPM=180°∠RPM=150°-xAs, PQR is straight line⇒∠RQN+∠PQN=180° Linear pair⇒∠PQN=180°-140°=40°Now we are given that LM is parallel to NQ⇒∠RPM=∠PQN Alternate interior angles⇒150°-x=40°⇒x=150°-40°⇒x=110° 5 View Full Answer Kanhaiya Mohan answered this extend NQ as an imaginary line to mr at point t such that NT is parallel to LM now, angle RQT= 180-140=40 In triangle QTR 40+30+x=180 x=110 as angle m is equal to angle t 1