In the given figure, BA is parallel to DE, prove that angle ABC+angle BCD=180+angle CDE

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In the given figure, BA is parallel to DE, prove that angle
ABC+angle BCD=180+angle CDE

Anuradha Sharma · Accepted Answer

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Draw a line MN parallel to AB and DE
Since DE and CM are paralel and CD is intersecting them so ∠1 = ∠3
1and ∠2+∠4=180Adding angle 1 both side we get ∠1+∠2+∠4=180+∠1 ∠BCD+∠ABC=180+∠3 Using equation 1 ∠BCD+∠ABC=180+∠CDEProved