In the given figure, ABC is a quadrant of a circle of radius 14 cm and a semicircle is drawn with BC as diameter. Find the area of the shaded region.
As ABC is a quadrant of the circle, ∠BAC will be of measure 90º.
In ΔABC,
BC2 = AC2 + AB2
= (14)2 + (14)2
Radius (r1) of semi-circle drawn on
Area of
Area of sector
= 154 − (154 − 98)
= 98 cm2