In the given figure, ABC is a quadrant of a circle of radius 14 cm and a semicircle is drawn with BC as diameter. Find the area of the shaded region.

As ABC is a quadrant of the circle, ∠BAC will be of measure 90º.

In ΔABC,

BC2 = AC2 + AB2

= (14)2 + (14)2

Radius (r1) of semi-circle drawn on

Area of

Area of sector

= 154 − (154 − 98)

= 98 cm2

  • 159
What are you looking for?