In the figure AB parallel to CD. If angle ABR = 45 degree and angle ROD = 105 degree then find angle ODC 

Dear student,


Let us construct the lines OQand RP.ABO= BPD = 45°In OPD, OPD +POD+ODP= 180°or, 45° +105° +ODP = 180°or, ODP= 180° - 45° - 105° = 30°Thus, ODC= 30°

Regards

  • 29
ABR=ODC (Alternative interior angles)
ODC= 45
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