In âˆ†PQR, PR = 8 cm, QR = 4 cm and PL = 5 cm Find : - Maths - Perimeter and Area

Question

In âˆ†PQR, PR = 8 cm, QR = 4 cm and PL = 5 cm Find
:

(a) area of âˆ†PQR
(b) QM

Lovina Kansal · Accepted Answer

Dear student
Clearly,△PLR is a right triangle
So, By pythagoras theoremPR2=PL2+LR2⇒82=52+LR2⇒LR2=64-25⇒LR2=39⇒LR=39cmArea of △PQR=12×QR×PL=12×39×4=239cm2    
(1)Clearly, ∠QMR is a right angleSo, Area of △PQR=12×PR×QM⇒239=12×8×QM⇒QM=392cm
Regards

In ∆PQR, PR = 8 cm, QR = 4 cm and PL = 5 cm. Find : (a) area of ∆PQR (b) QM

In ∆PQR, PR = 8 cm, QR = 4 cm and PL = 5 cm. Find :

(a) area of ∆PQR
(b) QM