IN GEIGER MARSDEN EXPERIMENT CALCULATE THE OF CLOSEST APPROACH TO THE NUCLEUS OF Z=75, WHEN AN ALPHA PARTICLE OF 5MEV ENERGY IMPINGS ON ITBEFORE IT COMES MOMENTARILY TO REST AND REVERES ITS DIRECTION.PLEASE ANSWER SOON
The distance of closest approach is given as
here
Z = 75
e = 1.6x10-19 C
E = 5 MeV = 5 X 1.6 X 10-13 J
and
1/4πε0 = 9x109 Nm2C-1
so,
r0 = [9x109 x 2x75x(1.6x10-19)2] / [5 X 1.6 X 10-13] m
which can be calculated...