IN GEIGER MARSDEN EXPERIMENT CALCULATE THE OF CLOSEST APPROACH TO THE NUCLEUS OF Z=75, WHEN AN ALPHA PARTICLE OF 5MEV ENERGY IMPINGS ON ITBEFORE IT COMES MOMENTARILY TO REST AND REVERES ITS DIRECTION.PLEASE ANSWER SOON

The distance of closest approach is given as

 

here

Z = 75

e = 1.6x10-19 C

E = 5 MeV = 5 X 1.6 X 10-13 J

and

1/4πε0 = 9x109 Nm2C-1

 

so,

r0 = [9x109 x 2x75x(1.6x10-19)2] / [5 X 1.6 X 10-13] m

 

which can be calculated...

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