in a unit cell atoms A ,B, C and D are present at corners , face centres , body centres and edge centres respectively.If atoms touching one of the plane passing through two diagonally opposite edges are removed , then what will be the formula of compound..... plz explain..?
by removing the plane passing through diagonally opposite edges
4 corners ,2face centres,1body centre and 2edge centres will be removed. therefore the effective atoms at corners wold be 4/8,at face centre4/2 and at edge centre 10/4.
A:B:C:D= 1:4:0:5
thus formula is AB4D5
4 corners ,2face centres,1body centre and 2edge centres will be removed. therefore the effective atoms at corners wold be 4/8,at face centre4/2 and at edge centre 10/4.
A:B:C:D= 1:4:0:5
thus formula is AB4D5
