In a closed system:A(s)⇌2B(g)+3C(g) if the partial pressure of C is doubled then partial pressure of B will be??

 For the closed system :

A(s)  2B (g) + 3C(g) 

   Kp = (pB)2 × (pC)3
Kp(pC)3= (pB)2       ............ equation 1


since Kp is constant thus if we double the partial pressure of C then p'C = 2pC
   Kp = (p'B)2 ×( p'C)3
   Kp = (p'B)2 × (2pC)3
     Kp(2pC)3= (p'B)2  Kp 8 (pC)3= (p'B)2  From equation 118 (pB)2   = (p'B)2   p'B = 122 pBThus pressure of B component will reduce by a factor of 22.    
   



 

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