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If√2 = 1.414,√3 =1.732 then find the value of :

4 ₊ 3

3√3 + 2√2 3√3 - 2√2

$\frac{4}{3 \sqrt{3} + 2 \sqrt{2}} + \frac{3}{3 \sqrt{3} - 2 \sqrt{2}} = \frac{12 \sqrt{3} - 8 \sqrt{2} + 9 \sqrt{3} + 6 \sqrt{2}}{(3 \sqrt{3} + 2 \sqrt{2}) (3 \sqrt{3} - 2 \sqrt{2})} = \frac{21 \sqrt{3} - 2 \sqrt{2}}{{(3 \sqrt{3})}^{2} - {(2 \sqrt{2})}^{2}} = \frac{21 \times 1.732 - 2 \times 1.414}{27 - 8} = \frac{33.542}{19} = 1.765368$

4

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