if z = x+iy and z^2 = a+ib where a,b,x,y are real numbers, show that 2x^2 = √a^2+b^2 + a

z2= a+ib x+iy2=  a+ib x2-y2+2ixy =   a+ib Comparing, we get x2-y2= a .....12xy = b x2+y2= x2-y22+4x2y2= a2+b2....2Adding equation 1 and 2, 2x2= a+a2+b2

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