if y = e^theta (2 sin theta + sin 2 theta), x = e^theta (2 cost theta + cos 2 theta), find dy/dx Share with your friends Share 0 Varun.Rawat answered this We have, y = eθ2 sin θ + sin 2θ⇒dydθ = eθ2cos θ + 2 cos 2θ + 2 sin θ + sin 2θeθ⇒dydθ =eθ2cos θ + 2 cos 2θ + 2 sin θ + sin 2θNow, x = eθ2 cos θ + cos 2θ⇒dxdθ = eθ-2 sin θ -2 sin 2θ + 2 cos θ + cos 2θeθ⇒dxdθ = eθ-2 sin θ -2 sin 2θ+2 cos θ + cos 2θNow, dydx = dydθ×dθdx = eθ2cos θ + 2 cos 2θ + 2 sin θ + sin 2θeθ-2 sin θ -2 sin 2θ+2 cos θ + cos 2θ⇒dydx = 2cos θ + 2 cos 2θ + 2 sin θ + sin 2θ-2 sin θ -2 sin 2θ+2 cos θ + cos 2θ -3 View Full Answer
