if x+y=5 and xy=4 find the value of x-y

Given: x + y= 5, xy= 4

To Find: Value of (x-y)

Sol:

Using identity, (x+y)²= x² + y² +2xy

                        (5)² = x² + y² +2(4)

                        25= x² + y² +8

                         x² + y² = 17.

Using Identity, (x-y)² = x² + y² -2xy

                       (x-y)² = 17- 2(4)

                       (x-y)² = 17-8

                      (x-y)² = 9

                       (x-y)= ±3

Therefore, The value of (x-y) is ±3.

Regards,

  • 2
Dear student,
Give x+y = 5 and xy=4
? x^2+y^2=(x+y)^2 - 4xy
= 5^2 -4(4)
= 25-16
=9
?(x-y)^2=x^2+y^2-2xy
By substituting the given values we get
(x-y)^2= 9-8
(x-y)^2=1
Square rooting on both sides
x-y= ?1
Therefore
x-y=?1

Hope you found this helpful,
Regards,
  • 0
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