If x=b+c-a, y = c+a-b, z = a + b -c, then prove that,x³+³+z³ − 3xyz = 4(a³ + b³ + c³-3abc). This question has not been answered yet! Don't worry! You can check out similar questions with solutions below ... equal then prove that either a = 0 or a3 + b3 + c3 = 3abc.Then prove that Then prove that ... )=0 are equal,then prove that either a=0 or a3+b3+c3=3abc. If 𝑝 = (2 − 𝑎) then prove that 𝑎 3 + 6𝑎𝑝 + 𝑝 3 − 8 =0