if x= 3 sin(theta) and y= 4 cos(theta), find the value of under root{16x(square)+9y(square)} Share with your friends Share 1 Lovina Kansal answered this Dear student We have,x=3sinθ and y=4cosθSo, 16x2+9y2=163sinθ2+94cosθ2=169sin2θ+916cos2θ=144sin2θ+144cos2θ=144sin2θ+cos2θ=144=12 Regards 1 View Full Answer K. Mani answered this TOO LONG 4 Sanchay answered this substitute the values of x and y given to u 2 Sai Vignesh Follow Me @sigvins... answered this usr6tu 2 Sai Vignesh Follow Me @sigvins... answered this XYTRUJ 0