if x= 3 sin(theta) and y= 4 cos(theta), find the value of under root{16x(square)+9y(square)}​

Dear student
We have,x=3sinθ and y=4cosθSo, 16x2+9y2=163sinθ2+94cosθ2=169sin2θ+916cos2θ=144sin2θ+144cos2θ=144sin2θ+cos2θ=144=12
Regards

  • 1
TOO LONG
  • 4
substitute the values of x and y given to u 
  • 2
usr6tu
  • 2
XYTRUJ
  • 0
What are you looking for?