If triangle ABC similar to triangle PQR , perimeter of triangle ABC = 32 cm, perimeter of triangle PQR = 48 cm and PR = 6cm then find the length of AC

ΔABC ~ ΔPQR,

therefore by CPST

AB/PQ = BC/QR = AC/PR = 32/48
AC/PR = 32/48     
AC/6 = 32/48       [ PR = 6cm ]
AC = 4cm
 


 

  • 11
Given: triangle ABC ∼ triangle PQR,  perimeter of triangle ABC = 32cm, perimeter of triangle PQR = 48cm and PR = 6cm 
since the y are similar, 
AB/PQ = BC/QR = AC/PR 
AC/PR = perimeter of triangle ABC/perimeter of triangle PQR 
AC/6 = 32/48 
AC*48 = 6*32 
therefore AC = 4cm 
 
  • 40

InΔABC,DE//BC so that AD=24cm,AE=32cm A and EC = 48 cm. Find AB. 

  • -1
AC/PR=32/48 AC/6=2/3 AC=4cm

  • 30
This can be the solution

  • 6
Given triangle abc similar to triangle pqr if ab/pq is 1/3 then find ratio of area of triangle abc to triangle pqr
  • 2
given:triangle ABC~triangle POR, area of triangle ABC=32,area of triangle PQR=48 and PR=6
by C.P.S.T.
AB/PQ=BC/QR=AC/PR
AC/PR=area of triangle ABC/area of triangle PQR
AC/6=32/48
AC/6=2/3
3*AC=2*6
3*AC=12
AC=4cm
  • 1
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