If the length of each edge of a cube is doubled, by how many times does its volume and surface area increase?

Let the length of each edge of a cube be 'a'
Surface area of cube ( S ) =
Volume of cube ( V ) =
If the length of each edge of the cube is doubled, 
Then, surface area of new cube =

Volume of new cube =
 

Therefore, by doubling each edge of a cube total surface area is increase by 4 times and volume is increased by 8 times.

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 Let The Edge Be "a"

Initial Surface Area = 6*a*a = 6a2

Initial Volume = a*a*a = a3

New Edge = 2a

New Surface Area = 6*2a*2a = 24a

 

New Volume = 2a*2a*2a = 8a3

Now As We Can See Volume Has Become 8 times Of Initial And Surface Area has become 4 times of initial.

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