if the equation ax^2 + (2-b)xy + 3y^2 - 6bx + 30y + 6b = 0 is circle then find a^2 + b^2 = ? Share with your friends Share 0 Vivek Rai answered this Dear student ax2+(2-b)xy+3y2-6bx+30y+6b=0 has to represent circle,then 2-b=0, and a=3,⇒b=2,a=3*as for a 2o equation, ax2+by2+2hxy+2gx+2fy+c=0, we must have a=b, and h=0As by applying these 2 conditions, we got a=3,b=2⇒a2+b2=9+4=13 Hope this clears your doubt With regards 2 View Full Answer