If the equation a - 5 x 2 + 2 a - 10 x + a + 10 = 0 has roots of the opposite sign, then
(A) a > 10                    (B) –15 < a < 5                (C) –10 < a < 5               (D) none of these

Hi, If equation ax2+bx+c=0 has roots of opposite sign then product of zeroes= negativeso ca<0 Here a+10a-5<0 on number line -<+++++-10------5++++++>so a -10,5 option C

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