if the area of an isosceles right triangle is 8cm,what is its perimeter

Let, base= x

AS an isoceles right triangle 2 sides are same so hight is also x.

Area= 1/2 x base x height

8cm=1/2 x base x height

8x2= XxX

16=x²

square root of 16 = x

4cm = x (x = base and height)

By pythagoras therom,

AC² = AB² + BC²

= (4)² + (4)²

= 16 + 16

= 32 cm

AC = square root of 32

AC = 4 root 2 cm

Perimof the triangle = x + x + x

= 4+4+4 root 2

= 8+ 4 root 2