If sum of the square of zeros of the quadratic polynomial f(x)=x2-8x+k is 40 find the value of K
Reply it fast..
given x2 + y2 = 40 (x and y are zeroes of quadratic equation)
we can write (x + y)2 - 2xy = 40 ------------------ 1
nw some of zeroes = x + y = -B/A = -(-8)=8
product of zeroes = xy = C/A = k
put value in equation 1
(8)2 - 2k = 40
64 - 40 = 2k
2k = 24
k = 12 answer
i think it will work
chill