If sec theta = - root 2 , and 3pi/2 Urgent. pls. Thnx. Share with your friends Share 0 Varun.Rawat answered this Your question is not clear, kindly recheck it and do get back to us. 0 View Full Answer Aisha Siddique answered this let theta be xsec x= -root2if sec x= +root2, then x= pi/4sec x= -root2 lies in the 2nd quadrant. hence, sec x= pi-pi/4 =3pi/4P.s.=3pi/4, pi+pi/4= 5pi/4G.s.= 2n pi+or-y = 2npi+or-3pi/4 where n belongs to Z 0