If S1 , S2 , S3 are the sum of n terms of three AP's the first term of each being unity and respective common diffrence being 1 , 2 , 3_ _ _ _ _. Prove that S1+S 3 = 2S2.

s1= [2a +(n-1)d]n/2

=[2a +n-1)n/2

s2=[2a+(n-1)2]n/2

=[2a+2n-2]n/2 =(2an +2n2 -2n)/2

s3=[2a+(n-1)3]n/2 =(2a+3n-3)n/2

s+s1=[2an+3n2 -3n +2an+n2-n]/2

=(4an+4n2-4n)/2

=2an+2n2 -2=2s2

hence proved

  • 22
it is wrong
 
  • -18
It will help you... Cheerrrrrssssss.....

  • 169
Perfect answer

  • 42
Its called a perfect answer.....oh yeahhhhh!!

  • -12
yaah you all are correct.you all had shown diffrent methods to solve it. Thumps Up Pls
  • -12
Expert,Now pls close this conversation....
  • -21
Very good Anwar husain
  • -13
thnx
 
  • 15
Ans

  • 23
Thanks to all experts
  • 3
Here’s the answer with best quality photo

  • -1
What are you looking for?