if p (x)=(x-a) q (x), then prove that, the degree of q (x) =degree of p (x)-1

Let qx=bxn+b1xn-1+......+bn ,Where degree=nThen,px=x-abxn+b1xn-1+......+bn=bxn+1+b1xn+......+bnx-abxn+ab1xn-1+......+ab=bxn+1+b1-abxn+......+bn-abSo, degree of px is n+1.Therefore,degree of qx=degree of px-1Hence Proved.

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