If cot^-1 (3/4) = X , find the value of sin x

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Please find below the solution to the asked query:

$$\begin{gathered} {\cot }^{-1}\left(\frac{3}{4}\right)=\mathrm{x} \\ \Rightarrow \cot \left(\mathrm{x}\right)=\frac{3}{4}=\frac{\mathrm{Base}\left(\mathrm{b}\right)}{\mathrm{Perpendicular}\left(\mathrm{p}\right)} \\ \mathrm{Hypotenuse}\left(\mathrm{h}\right) \mathrm{will} \mathrm{be} \mathrm{given} \mathrm{by}: \\ \Rightarrow \mathrm{h}=\sqrt{{\mathrm{b}}^2+{\mathrm{p}}^2}=\sqrt{3^2+4^2}=\sqrt{9+16}=5 \\ \sin \left(\mathrm{x}\right)=\frac{\mathrm{p}}{\mathrm{h}}=\frac{\mathbf{4}}{\mathbf{5}}\mathbf{ }\left(\mathbf{Answer}\right) \end{gathered}$$

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