if a sample of CuSO4.5H2O contains 64 gram sulphur then calculate mass of hydrogen atom present in sample

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32 g of S is present in 1 mol of CuSO4.5H2OSo, 64 g of S will be present in 132×64=2 mol of CuSO4.5H2ONow, 1 mol of CuSO4.5H2O has 10 g of HSo, 2 mol of CuSO4.5H2O contains 2×10=20 g of H

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20g of hydrogen atom will be present
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