if A=( 2x:x belongs to N}, B = { 3x; x belongs to N}, C={ 5x: x belongs to N}, then find ( A intersection B) intersection C.

then

(2,4,6...30,...60,...90) Since in all the

In 3x let x=12345... cases x belongs

then

(3,6,9,15...30,...60,...90) to a natural no

In 5x Let x=12345... hence .

then

(5,10,15,...30,...60,...90) x=12345...

A/B/C=(30,60,90,120...)