if A=( 2x:x belongs to N}, B = { 3x; x belongs to N}, C={ 5x: x belongs to N}, then find ( A intersection B) intersection C.
In 2x Let X=12345...
then
(2,4,6...30,...60,...90) Since in all the
In 3x let x=12345... cases x belongs
then
(3,6,9,15...30,...60,...90) to a natural no
In 5x Let x=12345... hence .
then
(5,10,15,...30,...60,...90) x=12345...
A/B/C=(30,60,90,120...)
then
(2,4,6...30,...60,...90) Since in all the
In 3x let x=12345... cases x belongs
then
(3,6,9,15...30,...60,...90) to a natural no
In 5x Let x=12345... hence .
then
(5,10,15,...30,...60,...90) x=12345...
A/B/C=(30,60,90,120...)