If 8l of water is poured in 192l of milk, what is the percentage of each mixture
Solution:
Given, 8L of water and 192L of milk
Given, 8L of water and 192L of milk
So, total amount of mixture= 8 + 192 = 200L
Now, percentage of 8L of water in the mixture = (8/200) × 100% = 4%
Percentage of 192L of milk in the mixture = (192/200) × 100% = 96%
Now, percentage of 8L of water in the mixture = (8/200) × 100% = 4%
Percentage of 192L of milk in the mixture = (192/200) × 100% = 96%