If 2a-b+c=0,prove that 4a2-b2+c2+4ac=0.

2a-b+c=02a+c=bTo Prove:-4a2-b2+c2+4ac=0LHS4a2-b2+c2+4ac=4a2+c2+4ac-b2=2a2+c2+22ac-b2=2a+c2-b2=b2-b2=0=RHSHence Proved

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2a - b + c = 0
or 2a + c = b
or (2a + c)2 = b2
or 4a2 + c2 + 4ac = b2
or 4a2 + c2 + 4ac - b2 = 0[proved]

 
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